When radiation of wavelength A is used to illuminate a metallic surface, the stopping potential is V . When the same surface is illuminated with radiation of wavelength 3 A , the stopping potential is V 4 . If the threshold wavelength for t

Question

When radiation of wavelength A is used to illuminate a metallic surface, the stopping potential is V . When the same surface is illuminated with radiation of wavelength 3 A , the stopping potential is V 4 . If the threshold wavelength for the metallic surface is n&#955; then value of n will be :

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Correct answer: 9

h c &#955; = &#981; + e V ...........(1) h c 3 &#955; = &#981; + e V 4 ---------(2) from (1) & (2) h c &#955; 1 - 1 3 = 3 4 e v hc &#955; 2 3 = 3 4 eV eV = 8 9 hc &#955; h c &#955; = &#981; + 8 9 h c &#955; &#981; = hc 9 &#955; = hc &#955; th &#955; t h = 9 &#955; &#8756; k = 9

When radiation of wavelength A is used to illuminate a metallic surface, the stopping potential is V . When the same surface is illuminated with radiation of wavelength 3 A , the stopping potential is V 4 . If the threshold wavelength for the metallic surface is nλ then value of n will be :

Correct answer

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More from Dual Nature of Matter

When radiation of wavelength A is used to illuminate a metallic surface, the stopping potential is V . When the same surface is illuminated with radiation of wavelength 3 A , the stopping potential is V 4 . If the threshold wavelength for the metallic surface is n&#955; then value of n will be :

Correct answer

Step-by-step solution

More from Dual Nature of Matter

When radiation of wavelength A is used to illuminate a metallic surface, the stopping potential is V . When the same surface is illuminated with radiation of wavelength 3 A , the stopping potential is V 4 . If the threshold wavelength for the metallic surface is nλ then value of n will be :