JEE Main20209 Jan 2020Morning ShiftPhysicsDual Nature of MatterActual
A particle moving with kinetic energy E has de Broglie wavelength λ . If energy Δ E is added to its energy, the wavelength become λ 2 . Value of Δ E , is:
Options
- AE
- B4 E
- C3 E
- D2 E
Correct answer
C. 3 E
Step-by-step solution
λ = h 2 K E m ⇒ λ ∝ 1 K E λ λ 2 = K E f K E i 4 K E i = K E f ⇒ Δ E = 4 K E i - K E i = 3 K E = 3 E