JEE Main201912 Apr 2019Morning ShiftPhysicsDual Nature of MatterActual
The stopping potential V o (in volt) as a function of frequency ( v ) for a sodium emitter, is shown in the figure. The work function of sodium, form the data plotted in the figure, will be: (Given: Planck’s constant h = 6.63 × 10 - 34 J s , electron charge ( e ) = 1.6 × 10 - 19 C )
Options
- A2.12 e V
- B1.82 e V
- C1.95 e V
- D1.66 e V
Correct answer
D. 1.66 e V
Step-by-step solution
From Einstein's photoelectric equation, h ν = ϕ + e V 0     . ⇒ V 0 = h ν e - ϕ e     . . . . . . 1 At ν = 4 × 10 14   Hz , V 0 = 0 . Putting the value in equation 1 , we get 0 = hv e - ϕ e So, Work function ( ϕ ) = h ν e    i n   e V = 6.63 × 10 - 34 × 4 × 10 14 1.6 × 10 - 19 = 1.66   e V