The maximum velocity of the photoelectrons emitted from the surface is v when light of frequency n falls on a metal surface. If the incident frequency is increased to 3 n , the maximum velocity of the ejected photoelectrons will be:

Step-by-step solution

According to Einstein's photoelectric effect, K E max = h c λ - ϕ The incident energy of the photon is E 1 = 1 2 m v 2 = h n - ϕ     . . . 1 If incident frequency increased to 3n E 2 = 1 2 m v 2 2 = 3 h n -   ϕ = 3 h n - ϕ + 2 ϕ   E 2 = 3   E 1 + 2 ϕ ⇒ 1 2 m v 2 2 = 3 2 m v 2 + 2 ϕ ⇒ v 2 2 = 3 v 2 + 4 ϕ m ⇒ v 2 > v 3