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When photons of wavelength λ 1 are incident on an isolated sphere, the corresponding stopping potential is found to be V . When photons of wavelength λ 2 are used, the corresponding stopping potential was thrice that of the above value. If light of wavelength λ 3 is used then find the stopping potential for this case:

Options

  1. Ah c e 1 λ 3 + 1 λ 2 - 1 λ 1
  2. Bh c e 1 λ 3 + 1 2 λ 2 - 1 λ 1
  3. Ch c e 1 λ 3 - 1 λ 2 - 1 λ 1
  4. Dh c e 1 λ 3 + 1 2 λ 2 - 3 2 λ 1

Correct answer

D. h c e 1 λ 3 + 1 2 λ 2 - 3 2 λ 1

Step-by-step solution

h c λ 1 = h c λ 0 + e V ...(i) h c λ 2 = h c λ 0 + 3 e V ...(ii) h c λ 3 = h c λ 0 + e V ′ ....(iii) Equation (i) and (ii) 3 2 λ 1 - 1 2 λ 2 = 1 λ 0 h c λ 3 - h c 3 2 λ 1 - 1 2 λ 2 = e V ′ h c e 1 λ 3 - 3 2 λ 1 + 1 2 λ 2 = V ′

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