JEE Main2016PhysicsDual Nature of MatterActual
When photons of wavelength λ 1 are incident on an isolated sphere, the corresponding stopping potential is found to be V . When photons of wavelength λ 2 are used, the corresponding stopping potential was thrice that of the above value. If light of wavelength λ 3 is used then find the stopping potential for this case:
Options
- Ah c e 1 λ 3 + 1 λ 2 - 1 λ 1
- Bh c e 1 λ 3 + 1 2 λ 2 - 1 λ 1
- Ch c e 1 λ 3 - 1 λ 2 - 1 λ 1
- Dh c e 1 λ 3 + 1 2 λ 2 - 3 2 λ 1
Correct answer
D. h c e 1 λ 3 + 1 2 λ 2 - 3 2 λ 1
Step-by-step solution
h c λ 1 = h c λ 0 + e V ...(i) h c λ 2 = h c λ 0 + 3 e V ...(ii) h c λ 3 = h c λ 0 + e V ′ ....(iii) Equation (i) and (ii) 3 2 λ 1 - 1 2 λ 2 = 1 λ 0 h c λ 3 - h c 3 2 λ 1 - 1 2 λ 2 = e V ′ h c e 1 λ 3 - 3 2 λ 1 + 1 2 λ 2 = V ′