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JEE Main 2009
Exam
JEE Main
Year
2009
Subject
Physics
Chapter
Dual Nature of Matter

JEE Main 2009 · Physics · Dual Nature of Matter

The surface of a metal is illuminated with the light of 400 ~nm ....

The surface of a metal is illuminated with the light of 400 nm400 \mathrm{~nm}. The kinetic energy of the ejected photoelectrons was found to be 1.68eV1.68 \mathrm{eV}. The work function of the metal is (hc=1240eVnm)(\mathrm{hc}=1240 \mathrm{eV} \mathrm{nm})

Options

  1. A3.09eV3.09 \mathrm{eV}
  2. B1.41eV1.41 \mathrm{eV}
  3. C151eV151 \mathrm{eV}
  4. D1.68eV1.68 \mathrm{eV}

Correct answer

B. 1.41eV1.41 \mathrm{eV}

Step-by-step solution

12mv2=eVo=1.68eV⇒hv=hcλ=1240evnm400nm=3.1eV⇒3.1eV=W0+1.6eV∴W0=1.42eV\begin{aligned} \frac{1}{2} \mathrm{mv}^2=\mathrm{eV}_{\mathrm{o}}=1.68 \mathrm{eV} \Rightarrow \mathrm{hv}=\frac{\mathrm{hc}}{\lambda}=\frac{1240 \mathrm{evnm}}{400 \mathrm{ nm}}=3.1 \mathrm{eV} \Rightarrow3.1 \mathrm{eV}=\mathrm{W}_{0}+1.6 \mathrm{eV}\\ & \therefore \quad \mathrm{W}_{0}=1.42 \mathrm{eV} \end{aligned}
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