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Two identical photocathodes receive light of frequencies f ₁ and f ₂ . If the velocities of the photo electrons (of mass m ) coming out are respectively v ₁ and v ₂ , then

Options

  1. Av₁^2-v₂^2= 2 h m (f₁-f₂ )
  2. Bv₁+v₂= [ 2 h m (f₁+f₂ ) ]^ 1 / 2
  3. Cv₁^2+v₂^2= 2 h m (f₁+f₂ )
  4. Dv ₁- v ₂= [ 2 h ~m ( f ₁- f ₂ ) ]^ 1 / 2

Correct answer

A. v₁^2-v₂^2= 2 h m (f₁-f₂ )

Step-by-step solution

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