A square loop of side 2 cm is placed in a time varying magnetic field with magnitude as B = 0.4 (300t) Tesla. The normal to the plane of loop makes an angle of 60° with the field. The maximum induced emf produced in the loop is __________ mV.

Step-by-step solution

Given: Side of the square loop, a = 2 cm = 2 10⁻² m Area of the loop, A = a^2 = 4 10⁻⁴ m ^2 Magnetic field, B = 0.4 (300t) T Angle between the normal to the plane and the magnetic field, = 60^ The magnetic flux through the loop is given by: = B A = B A = (0.4 (300t))(4 10⁻⁴) (60^ ) = 1.6 10⁻⁴ (300t) 1 2 = 0.8 10⁻⁴ (300t) Wb By Faraday's law of induction, the induced emf is: e = - d dt e = - d dt (0.8 10⁻⁴ (300t)) e = -0.8 10⁻⁴ 300 (300t) e = -240 10⁻⁴ (300t) V e = -24 10⁻³ (300t) V The maximum induced emf is the am