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JEE Main20265 April 2026Morning ShiftPhysicsGravitationActual

When one moves from a point 16 km below the earth's surface to a point 16 km above the earth's surface. The change in g is approximately %. The value of is _____. (Take radius of the earth = 6400 km.)

Options

  1. A0.12
  2. B0.25
  3. C0.50
  4. D0.75

Correct answer

B. 0.25

Step-by-step solution

The acceleration due to gravity at a depth d below the earth's surface is given by: g_d = g (1 - d R ) The acceleration due to gravity at a height h above the earth's surface (for h R ) is given by: g_h = g (1 - 2h R ) Given d = 16 km and h = 16 km, we can find the values of g_d and g_h : g_d = g (1 - 16 6400 ) = g (1 - 1 400 ) g_h = g (1 - 2 16 6400 ) = g (1 - 2 400 ) The magnitude of the change in acceleration due to gravity when moving from the depth d to the height h is: g = g_d - g_h = g (1 - 1 400 ) - g (1 -

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