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JEE Main20249 Apr 2024Evening ShiftPhysicsKinetic Theory of GasesActual

The temperature of a gas is -78^ C and the average translational kinetic energy of its molecules is K . The temperature at which the average translational kinetic energy of the molecules of the same gas becomes 2 ~K is :

Options

  1. A127^ C
  2. B117^ C
  3. C-39^ C
  4. D-78^ C

Correct answer

B. 117^ C

Step-by-step solution

aligned & K . E = nf ₁ RT 2 & ~T _ i =-78^ C 273+ [-78^ C ]=195 ~K aligned K.E T To double the K.E energy temp also become double aligned & T _ f =390 ~K & ~T _ f =117^ C aligned

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