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JEE Main202310 Apr 2023Morning ShiftPhysicsKinetic Theory of GasesActual

Match List I with List II: List I List II (A) 3 Translational degrees of freedom (I) Monoatomic gases (B) 3 Translational, 2 rotational degrees of freedoms (II) Polyatomic gases (C) 3 Translational, 2 rotational and 1 vibrational degrees of freedom (III) Rigid diatomic gases (D) 3 Translational, 3 rotational and more than one vibrational degrees of freedom (IV) Nonrigid diatomic gases Choose the correct answer from t

Options

  1. AA - I ,   B - III ,   C - IV ,   D - II
  2. BA - IV ,   B - III ,   C - II ,   D - I
  3. CA - IV ,   B - II ,   C - I ,   D - III
  4. DA - I ,   B - IV ,   C - III ,   D - II

Correct answer

A. A - I ,   B - III ,   C - IV ,   D - II

Step-by-step solution

The formula for degree of freedom is given by f = 3 N - k where N is the number of particles, k is the individual relationship in the system. For a monoatomic gas particle, N = 1 ,   k = 0 . So, f = 3 Hence, monoatomic gas has 3 translational degree of freedom. For a rigid diatomic gas molecule, there are 5 degrees of freedom, 3 translational and 2 rotational. A diatomic gas can have two extra degrees of freedom due to rotation along two independent axes. A non rigid diatomic molecule has one extra degree of f

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