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JEE Main 202324 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
24 January
Shift
Morning Shift
Subject
Physics
Chapter
Kinetic Theory of Gases

JEE Main 2023 · 24 January · Morning Shift · Physics · Kinetic Theory of Gases

Given below are two statements: Statement I : The temperature of a...

Given below are two statements:
Statement I: The temperature of a gas is −73°C- 73 ° C. When the gas is heated to 527°C527 ° C, the root mean square speed of the molecules is doubled.
Statement II : The product of pressure and volume of an ideal gas will be equal to translational kinetic energy of the molecules.
In the light of the above statements, choose the correct answer from the options given below:

Options

  1. ABoth Statement I and Statement II are true
  2. BStatement I is true but Statement II is false
  3. CBoth Statement I and Statement II are false
  4. DStatement I is false but Statement II is true

Correct answer

B. Statement I is true but Statement II is false

Step-by-step solution

Given:

T1=−73°C=(−73+273)K=200K{T}_{1} = - 73 ° C = \left(- 73 + 273\right)K = 200K

and T2=527°C=(527+273)K=800K{T}_{2} = 527 ° C = \left(527 + 273\right)K = 800K

Therefore,

Vrms,1Vrms,2=3RT1M3RT2M=T1T2\dfrac{{V}_{rms, 1}}{{V}_{rms, 2}} = \dfrac{\sqrt{\dfrac{3R{T}_{1}}{M}}}{\sqrt{\dfrac{3R{T}_{2}}{M}}} = \sqrt{\dfrac{{T}_{1}}{{T}_{2}}}

=200800=12= \sqrt{\dfrac{200}{800}} = \dfrac{1}{2}

Vrms,2=2Vrms,1{V}_{rms, 2} = 2{V}_{rms, 1}

Hence,

Statement-I is true.

Now,

PV=nRTPV = nRT

But translational KE=32nRTKE = \dfrac{3}{2}nRT

Hence, Statement-II is false.

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