JEE Main202324 Jan 2023Morning ShiftPhysicsKinetic Theory of GasesActual
Given below are two statements: Statement I : The temperature of a gas is - 73 ° C . When the gas is heated to 527 ° C , the root mean square speed of the molecules is doubled. Statement II : The product of pressure and volume of an ideal gas will be equal to translational kinetic energy of the molecules. In the light of the above statements, choose the correct answer from the options given below:
Options
- ABoth Statement I and Statement II are true
- BStatement I is true but Statement II is false
- CBoth Statement I and Statement II are false
- DStatement I is false but Statement II is true
Correct answer
B. Statement I is true but Statement II is false
Step-by-step solution
Given: T 1 = - 73   ° C = - 73 + 273   K = 200   K and T 2 = 527 ° C = 527 + 273   K = 800   K Therefore, V r m s ,   1 V r m s ,   2 = 3 R T 1 M 3 R T 2 M = T 1 T 2 = 200 800 = 1 2 V r m s ,   2 = 2   V r m s ,   1 Hence, Statement-I is true. Now, P V = n R T But translational KE = 3 2 nRT Hence, Statement-II is false.