A mixture of hydrogen and oxygen has volume 2000 cm 3 , temperature 300 K , pressure 100 kPa and mass 0 . 76 g . The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be [Take gas constant R = 8 . 3 J K - 1 mol - 1 ]

Step-by-step solution

From the ideal gas equation, total number of moles in the mixture are, n = P V R T = 2 × 10 - 3 × 100 × 10 3 × 3 25 × 300 ⇒ n = 2 25 = 0 . 08 If number of moles of oxygen are n 1 and of hydrogen are n 2 n 1 + n 2 = n = 0 . 08 … 1 And total mass of the mixture n 1 32 + n 2 2 = 0 . 76 … 2 Solving the above equations, n 1 = 0 . 02 and n 2 = 0 . 06 n 2 n 1 = 3