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JEE Main202124 Feb 2021Evening ShiftPhysicsKinetic Theory of GasesActual

The root-mean-square speed of molecules of a given mass of a gas at 27 ° C and 1 atmosphere pressure is 200 m s - 1 . The root-mean-square speed of molecules of the gas at 127 ° C and 2 atmosphere pressure is x 3 m s - 1 . The value of x will be __________.

Correct answer

0

Step-by-step solution

v rms = 3 R T M ⇒ v rms ∝ T ⇒ v rms 2 v rms 1 = T 2   T 1 = 400 300 = 2 3 v rms 2 = 2 3 v rms 1 = 2 3 × 200 ⇒ v rms 2 = 400 3   m   s - 1 .

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