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JEE Main 20203 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
3 September
Shift
Morning Shift
Subject
Physics
Chapter
Kinetic Theory of Gases

JEE Main 2020 · 3 September · Morning Shift · Physics · Kinetic Theory of Gases

Consider a gas of triatomic molecules. The molecules are assumed to...

Consider a gas of triatomic molecules. The molecules are assumed to be triangular and made of massless rigid rods whose

Consider a gas of triatomic molecules. The molecules are assumed to be triangular and made of massless rigid rods whose vertices are occupied by atoms. The internal energy of a mole of the gas at temperature T is:

Options

  1. A52RT\dfrac{5}{2}RT
  2. B32RT\dfrac{3}{2}RT
  3. C92RT\dfrac{9}{2}RT
  4. D3RT3RT

Correct answer

D. 3RT3RT

Step-by-step solution

The formula of internal energy of a gas is given by

U=f2RTU = \dfrac{f}{2}RT

Here RisthegasconstantandR is the gas constant andTistemperature.</p><p>(R=8.314Jmol−1K−1)is temperature.</p><p>\left(R = 8 . 314J{mol}^{- 1}{K}^{- 1}\right)

For the given configuration of triatomic molecules, the degree of freedom f=6f = 6

⇒U=62RT=3RT⇒ U = \dfrac{6}{2}RT = 3RT

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