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JEE Main 201911 JanuaryMorning Shift
Exam
JEE Main
Year
2019
Date
11 January
Shift
Morning Shift
Subject
Physics
Chapter
Kinetic Theory of Gases

JEE Main 2019 · 11 January · Morning Shift · Physics · Kinetic Theory of Gases

A gas mixture consists of 3 moles of oxygen and 5 moles of argon at...

A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T. Considering only translational and rotational modes, the total internal energy of the system is

Options

  1. A15RT15 \mathrm{RT}
  2. B12RT12 \mathrm{RT}
  3. C4RT4 \mathrm{RT}
  4. D20RT20 \mathrm{RT}

Correct answer

A. 15RT15 \mathrm{RT}

Step-by-step solution

U=f12n1RT+f22n2RTU=\frac{f_{1}}{2} n_{1} R T+\frac{f_{2}}{2} n_{2} R T Considering translational and rotational modes, degrees of freedom f1=5\mathrm{f}_{1}=5 and f2=3\mathrm{f}_{2}=3 ∴u=52(3RT)+32×5RT\therefore \mathrm{u}=\frac{5}{2}(3 \mathrm{RT})+\frac{3}{2} \times 5 \mathrm{RT} U=15RT\mathrm{U}=15 \mathrm{RT}
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