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JEE Main 20163 April
Exam
JEE Main
Year
2016
Date
3 April
Subject
Physics
Chapter
Kinetic Theory of Gases

JEE Main 2016 · 3 April · Physics · Kinetic Theory of Gases

An ideal gas undergoes a quasi-static, reversible process in which...

An ideal gas undergoes a quasi-static, reversible process in which its molar heat capacity C remains constant. If during this process the relation of pressure P and volume V is given by PVn=P{V}^{n} = constant, then n is given by (Here CP{C}_{P} and CV{C}_{V} are molar specific heat at constant pressure and constant volume, respectively) :

Options

  1. An=CP−CC−CVn = \dfrac{{C}_{P} - C}{C - {C}_{V}}
  2. Bn=C−CVC−CPn = \dfrac{C - {C}_{V}}{C - {C}_{P}}
  3. Cn=CPCVn = \dfrac{{C}_{P}}{{C}_{V}}
  4. Dn=C−CPC−CVn = \dfrac{C - {C}_{P}}{C - {C}_{V}}

Correct answer

D. n=C−CPC−CVn = \dfrac{C - {C}_{P}}{C - {C}_{V}}

Step-by-step solution

PVn=kP{V}^{n} = k

C=Cv+R1−nC = {C}_{v} + \dfrac{R}{1 - n} ; C−Cv=R1−nC - {C}_{v} = \dfrac{R}{1 - n}

1−n=RC−Cv1 - n = \dfrac{R}{C - {C}_{v}} ; n=1−RC−Cvn = 1 - \dfrac{R}{C - {C}_{v}}

n=C−Cv−RC−Cvn = \dfrac{C - {C}_{v} - R}{C - {C}_{v}} ; n=C−Cv−(Cp−Cv)C−Cvn = \dfrac{C - {C}_{v} - \left({C}_{p} - {C}_{v}\right)}{C - {C}_{v}}

n=C−Cv−Cp+CvC−Cvn = \dfrac{C - {C}_{v} - {C}_{p} + {C}_{v}}{C - {C}_{v}} ; n=C−CpC−Cvn = \dfrac{C - {C}_{p}}{C - {C}_{v}}
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