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JEE Main2014PhysicsKinetic Theory of GasesActual

A gas molecule of mass M at the surface of the earth has kinetic energy equivalent to 0 ° C . If it were to go up straight without colliding with any other molecules, how high it would rise? Assume that the height attained is much less than the radius of the earth. ( k B is Boltzmann constant)

Options

  1. A273 k B 2 M g
  2. B8 1 9 k B 2 M g
  3. C0
  4. D5 4 6 k B 3 M g

Correct answer

B. 8 1 9 k B 2 M g

Step-by-step solution

M g h = 1 2 M v rms 2 = 1 2 M 3 k T m ⇒ v rms 2 = 819 k M Now apply v 2 = u 2 − 2 g h undefined

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