A block is sliding down on an inclined plane of slope $\theta$ and at an instant $t=0$ this block is given an upward momentum so that it starts moving up on the inclined surface with velocity $u$ . The distance $(S)$ travelled by the block before its velocity become zero, is $\_\_\_\_$ .
( $g=$ gravitational acceleration)

Question

A block is sliding down on an inclined plane of slope

\theta

and at an instant

t=0

this block is given an upward momentum so that it starts moving up on the inclined surface with velocity

u

. The distance

(S)

travelled by the block before its velocity become zero, is

\_\_\_\_

.
(

g=

gravitational acceleration)

Quantrex Academy · Accepted Answer

Correct answer: B. u^ 2 2 g θ

a = -g θ V^2 = U^2 + 2as 0 = u^2 - 2g θ · s s = (u^2)/(2g θ)

A block is sliding down on an inclined plane of slope θ and at an...