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JEE Main 20257 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Morning Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2025 · 7 April · Morning Shift · Physics · Laws of Motion

A cubic block of mass m is sliding down on an inclined plane at 60^...

A cubic block of mass mm is sliding down on an inclined plane at 60∘60^{\circ} with an acceleration of g2\frac{\mathrm{g}}{2}, the value of coefficient of kinetic friction isA cubic block of mass m is sliding down on an inclined plane at 60^ with an acceleration of g 2 , the value of

Options

  1. A3−1\sqrt{3}-1
  2. B32\frac{\sqrt{3}}{2}
  3. C23\frac{\sqrt{2}}{3}
  4. D1−321-\frac{\sqrt{3}}{2}

Correct answer

A. 3−1\sqrt{3}-1

Step-by-step solution

A cubic block of mass m is sliding down on an inclined plane at 60^ with an acceleration of g 2 , the value of
mgsin⁡60∘−μmgcos⁡60∘=ma\mathrm{mg} \sin 60^{\circ}-\mu \mathrm{mg} \cos 60^{\circ}=\mathrm{ma}
gsin⁡60−μgcos⁡60=g2g \sin 60-\mu g \cos 60=\frac{g}{2}
32−μ2=12\frac{\sqrt{3}}{2}-\frac{\mu}{2}=\frac{1}{2}
μ=3−1\mu=\sqrt{3}-1
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