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JEE Main20249 Apr 2024Evening ShiftPhysicsLaws of MotionActual

A 1 ~kg mass is suspended from the ceiling by a rope of length 4 ~m . A horizontal force ' F ' is applied at the mid point of the rope so that the rope makes an angle of 45^ with respect to the vertical axis as shown in figure. The magnitude of F is : (Assume that the system is in equilibrium and g=10 ~m / s ^2 )

Options

  1. A10 ~N
  2. B10 2 ~N
  3. C1 ~N
  4. D1 10 2 N

Correct answer

A. 10 ~N

Step-by-step solution

aligned & T ₁ 45^ = F & T ₁ 45^ = T ₂=1 g & 45^ = F g & F =10 ~N aligned

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