JEE Main20245 Apr 2024Morning ShiftPhysicsLaws of MotionActual
A wooden block of mass 5 ~kg rests on a soft horizontal floor. When an iron cylinder of mass 25 ~kg is placed on the top of the block, the floor yields and the block and the cylinder together go down with an acceleration of 0.1 ~ms ⁻² . The action force of the system on the floor is equal to:
Options
- A196 ~N
- B291 ~N
- C294 ~N
- D297 ~N
Correct answer
B. 291 ~N
Step-by-step solution
Taking g =9.8 ~m / s ^2 aligned & 294- N =30 0.1 & ~N =291 aligned