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JEE Main 20241 FebruaryEvening Shift
Exam
JEE Main
Year
2024
Date
1 February
Shift
Evening Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2024 · 1 February · Evening Shift · Physics · Laws of Motion

A cricket player catches a ball of mass 120g moving with 25m s ^ -...

A cricket player catches a ball of mass 120g120g moving with 25ms−125m{s}^{- 1} speed. If the catching process is completed in 0.1s0 . 1s then the magnitude of force exerted by the ball on the hand of player will be(in SI unit):

Options

  1. A2424
  2. B1212
  3. C2525
  4. D3030

Correct answer

D. 3030

Step-by-step solution

Average force exerted will be, Fav=∣\Deltap\Deltat∣{F}_{av} = \left|\dfrac{\Deltap}{\Deltat}\right|

=∣0−0.12×250.1∣=30N= \left|\dfrac{0 - 0 . 12 \times 25}{0 . 1}\right| = 30N

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