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JEE Main 20241 FebruaryMorning Shift
Exam
JEE Main
Year
2024
Date
1 February
Shift
Morning Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2024 · 1 February · Morning Shift · Physics · Laws of Motion

Consider a block and trolley system as shown in figure. If the...

Consider a block and trolley system as shown in figure. If the coefficient of kinetic friction between the trolley and the surface is 0.040 . 04, the acceleration of the system in ms−2m{s}^{- 2} is: (Consider that the string is massless and unstretchable and the pulley is also massless and frictionless) :

Consider a block and trolley system as shown in figure. If the coefficient of kinetic friction between the trolley and

Options

  1. A33
  2. B44
  3. C22
  4. D1.21 . 2

Correct answer

C. 22

Step-by-step solution

Consider a block and trolley system as shown in figure. If the coefficient of kinetic friction between the trolley and

Maximum kinetic friction acting, fk=\muN=0.04×20g=8{f}_{k} = \muN = 0 .04 \times 20g = 8 Newton

Therefore, acceleration of the system will bea=60−826=2ms−2a = \dfrac{60 - 8}{26} = 2m{s}^{- 2}

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