A block of mass 5kg is placed on a rough inclined surface as shown in the figure. If → F 1 is the force required to just move the block up the inclined plane and → F 2 is the force required to just prevent the block

Correct answer: B. 5 3 N Limiting friction force is, f _ = μ(mgcosθ) = 0 .1 × 50 × 3 2 = 2 .5 3 N For first case: We can write, F _ 1 = mgsinθ + f _ = 25 + 2 .5 3 For second case: F _ 2 = mgsinθ - f _ = 25 - 2 .5 3 ∴ F _ 1 - F _ 2 = 5 3 N

JEE Main 202431 JanuaryEvening Shift

Exam: JEE Main
Year: 2024
Date: 31 January
Shift: Evening Shift
Subject: Physics
Chapter: Laws of Motion

JEE Main 2024 · 31 January · Evening Shift · Physics · Laws of Motion

A block of mass 5kg is placed on a rough inclined surface as shown...

A block of mass $5kg$ is placed on a rough inclined surface as shown in the figure. If $\overset{\to}{F}1$ is the force required to just move the block up the inclined plane and $\overset{\to}{F}2$ is the force required to just prevent the block from sliding down, then the value of $\left|\overset{\to}{F}1\right| - \left|\overset{\to}{F}2\right| is: [Use$ g = 10m{s}^{- 2} $]</p><img src="https://cdn-question-pool.Quantrex.app/pyq/jee_main/0573a36f-bf6d-48d0-816c-4653d16aba81.png" style="width: 200px; height: 185px;"/>$

Options

A $25\sqrt{3}N$
B $5\sqrt{3}N$
C $\dfrac{5\sqrt{3}}{2}N$
D $10N$

Correct answer

B. $5\sqrt{3}N$

Step-by-step solution

Limiting friction force is, ${f}_\max = \mu\left(mgcos\theta\right)$

$= 0 .1 \times \dfrac{50 \times \sqrt{3}}{2}$

$= 2 .5 \sqrt{3}N$

For first case:

A block of mass 5kg is placed on a rough inclined surface as shown in the figure. If → F 1 is the force required to

We can write, ${F}_{1} = mgsin\theta + {f}_\max$

$= 25 + 2 .5 \sqrt{3}$

For second case:

A block of mass 5kg is placed on a rough inclined surface as shown in the figure. If → F 1 is the force required to

${F}_{2} = mgsin\theta - {f}_\max$

$= 25 - 2 .5 \sqrt{3}$

$∴ {F}_{1} - {F}_{2} = 5\sqrt{3}N$

Practice Laws of Motion on Quantrex Academy →

More from Laws of Motion

A block takes t time to slide down a plane inclined at 45° to the horizontal. If the… JEE Main 2026 Two blocks ( P and Q ) with respectively masses 2 kg and 1.5 kg are joined by a massless… JEE Main 2026 A mass of 1 kg is kept on an inclined plane with 30° inclination with respect to… JEE Main 2026 Three masses m_1 = 4 kg, m_2 = 4 kg and m_3 = 6 kg are suspended from a fixed smooth… JEE Main 2026 A wedge Y with mass of 10 kg and all frictionless surfaces and the inclined surface… JEE Main 2026 At t=0 , a body of mass 100 g starts moving under the influence of a force (5 i +10 j )… JEE Main 2026 The time taken by a block of mass m to slide down from the highest point to the lowest… JEE Main 2026 A 0.5 kg mass is in contact against the inner wall of a cylindrical drum of radius 4 m… JEE Main 2026 Full Laws of Motion list All JEE Main PYQs