JEE Main202430 Jan 2024Evening ShiftPhysicsLaws of MotionActual
A block of mass m is placed on a surface having vertical cross section given by y = x 2 4 . If coefficient of friction is 0 . 5 , the maximum height above the ground at which block can be placed without slipping is:
Options
- A1 4 m
- B1 2 m
- C1 6 m
- D1 3 m
Correct answer
A. 1 4 m
Step-by-step solution
At equilibrium, tan θ = μ . Now, tan θ is slope of the curve. Therefore, tan θ = d y d x = x 2 Now, x 2 = 0 . 5 ⇒ x = 1 Required height y = x 2 4 = 1 4 m .