A stone of mass 900 g is tied to a string and moved in a vertical circle of radius 1 m making 10 rpm . The tension in the string, when the stone is at the lowest point is (if π 2 = 9 . 8 and g = 9 . 8 m s - 2 )

Step-by-step solution

Given that Given the mass m = 900 g = 900 1000 kg = 9 10 kg , The radius of the circular path r = 1 m And, the angular velocity ω = 2 πN 60 = 2 π ( 10 ) 60 = π 3 rad s - 1 With reference to the above diagram, the formula to calculate the tension at the lowermost point can be written as T - m g = m r ω 2 ⇒ T = m g + m r ω 2 . . . 1 From equation (1), it follows that T = 9 10 × 9 . 8 + 9 10 × 1 π 3 2 = 8 . 82 + 9 10 × π 2 9 = 8 . 82 + 0 . 98 = 9 . 8 N