JEE Main202315 Apr 2023Morning ShiftPhysicsLaws of MotionActual
The position vector of a particle related to time t is given by r → = 10 t i ^ + 15 t 2 j ^ + 7 k ^ m . The direction of net force experienced by the particle is :
Options
- APositive x -axis
- BIn   x - y plane
- CPositive y -axis
- DPositive z -axis
Correct answer
C. Positive y -axis
Step-by-step solution
Given, the position vector of the particle is r → = 10 t i ^ + 15 t 2 j ^ + 7 k ^ The velocity of the particle can be calculated as follows: v → = d r → d t = d d t 10 t i ^ + 15 t 2 j ^ + 7 k ^ =   10 i ^ + 30 t j ^ And, the acceleration of the particle is given by a → = d v → d t = d d t 10 i ^ + 30 t j ^ = 30 j ^ Hence, the force on the particle can be written as F → = m a → = 30 m j ^