As shown in figure, a 70kg garden roller is pushed with a force of...

As shown in figure, a $70kg$ garden roller is pushed with a force of $\overset{\to}{F} = 200N$ at an angle of $30 °$ with horizontal. The normal reaction on the roller is (Given $g = 10m{s}^{- 2}$ )

As shown in figure, a 70kg garden roller is pushed with a force of → F = 200N at an angle of 30 ° with horizontal. The

Options

A $800\sqrt{2}N$
B $600N$
C $800N$
D $200\sqrt{3}N$

Correct answer

C. $800N$

Step-by-step solution

As shown in figure, a 70kg garden roller is pushed with a force of → F = 200N at an angle of 30 ° with horizontal. The

Component of the force perpendicular to the ground,

Fsin30 ° $.</p><p>Now for equilibrium along vertical direction, we get</p><p>$ N = mg + Fsin30 ° = 70 \times 10 + 200 \times \dfrac{1}{2} = 800N

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