As per given figure, a weightless pulley P is attached on a double inclined frictionless surface. The tension in the string (massless) will be (if g = 10 m s - 2 )

Step-by-step solution

The magnitude of acceleration of both the blocks will be same and is given by a = 4   g   sin   60 ∘ - g   sin   30 ∘ 4 + 1 = 20 3 - 5 5 a = 4 3 - 1 m   s - 1 Applying Newton's second law for second block (along the direction parallel to the incline on which it is placed) T - 5 = 1 × a ⇒ T = 5 + 4 3 - 1 = 4 3 + 1   N