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JEE Main 202227 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
27 July
Shift
Evening Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2022 · 27 July · Evening Shift · Physics · Laws of Motion

A block of mass M slides down on a rough inclined plane with...

A block of mass MM slides down on a rough inclined plane with constant velocity. The angle made by the incline plane with horizontal is θ\theta. The magnitude of the contact force will be :A block of mass M slides down on a rough inclined plane with constant velocity. The angle made by the incline plane

Options

  1. AMgMg
  2. BMgcos\theta
  3. CMgsinθ+Mgcosθ\sqrt{Mgsin\theta + Mgcos\theta}
  4. DMgsin\theta\sqrt{1 + \mu}

Correct answer

A. MgMg

Step-by-step solution

A block of mass M slides down on a rough inclined plane with constant velocity. The angle made by the incline plane

As the block moves with constant velocity, so force on the block should be balanced. The forces acting on the block are its weight, normal contact force and friction. The contact force is vector sum of normal contact and friction. As the forces are balanced, the contact force should be equal and opposite to its weight.

∴∴Contact force =Mg= Mg

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