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JEE Main202227 Jul 2022Morning ShiftPhysicsLaws of MotionActual

A bag is gently dropped on a conveyor belt moving at a speed of 2 m s - 1 . The coefficient of friction between the conveyor belt and bag is 0 . 4 Initially, the bag slips on the belt before it stops due to friction. The distance travelled by the bag on the belt during slipping motion is : [Take g = 10 m s - 2 ]

Options

  1. A2   m
  2. B0 . 5   m
  3. C3 . 2   m
  4. D0 . 8   ms

Correct answer

B. 0 . 5   m

Step-by-step solution

When the bag is dropped on the conveyor belt, the acceleration of the bag will be a = μ g = 4   m   s - 2 The bag will stop moving on the conveyor when the velocity of the bag and the velocity of the conveyor becomes equal. u = 0 ,   v = 2   m   s - 1 Using the equation of motion for constant acceleration, v 2 = u 2 + 2 a s ⇒ s = 0 . 5   m

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