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JEE Main 202226 JulyMorning Shift
Exam
JEE Main
Year
2022
Date
26 July
Shift
Morning Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2022 · 26 July · Morning Shift · Physics · Laws of Motion

A monkey of mass 50kg climbs on a rope which can withstand the...

A monkey of mass 50kg50kg climbs on a rope which can withstand the tension \left(T\right) of 350N.Ifmonkeyinitiallyclimbsdownwithanaccelerationof. If monkey initially climbs down with an acceleration of4m{s}^{- 2}andthenclimbsupwithanaccelerationofand then climbs up with an acceleration of5m{s}^{- 2}.Choosethecorrectoption(g=10ms−2). Choose the correct option \left(g = 10m{s}^{- 2}\right)A monkey of mass 50kg climbs on a rope which can withstand the tension (T) of 350N . If monkey initially climbs downA monkey of mass 50kg climbs on a rope which can withstand the tension (T) of 350N . If monkey initially climbs down

Options

  1. AT=700NT = 700N while climbing upward
  2. BT=350NT = 350N while going downward
  3. CRope will break while climbing upward
  4. DRope will break while going downward

Correct answer

C. Rope will break while climbing upward

Step-by-step solution

Let a1{a}_{1} be the acceleration of monkey while moving down.

F.B.D of monkey while moving downward

A monkey of mass 50kg climbs on a rope which can withstand the tension (T) of 350N . If monkey initially climbs down

Using Newton's second law of motion,

mg−T=ma1mg - T = m{a}_{1}

∴500−T=50×4⇒T=300N∴ 500 - T = 50 \times 4 ⇒ T = 300N

Let a2{a}_{2} be the acceleration of monkey while moving up.

F.B.D of monkey while moving up

A monkey of mass 50kg climbs on a rope which can withstand the tension (T) of 350N . If monkey initially climbs down

Using Newton's second law of motion

T−mg=ma2T - mg = m{a}_{2}

⇒T−500=50×5⇒ T - 500 = 50 \times 5

⇒T=750N⇒ T = 750N

Breaking strength of rope =750−300=350N= 750 - 300 = 350N

∴∴ Rope will break while monkey is moving upward.

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