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JEE Main 202228 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
28 June
Shift
Morning Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2022 · 28 June · Morning Shift · Physics · Laws of Motion

A hanging mass M is connected to a four times bigger mass by using...

A hanging mass MM is connected to a four times bigger mass by using a string pulley arrangement, as shown in the figure. The bigger mass is placed on a horizontal ice-slab and being pulled by 2Mg2Mg force. In this situation, tension in the string is x5Mg\dfrac{x}{5}Mg for x=x =_____. Neglect mass of the string and friction of the block (bigger mass) with ice slab.
(Given g=g = acceleration due to gravity)

A hanging mass M is connected to a four times bigger mass by using a string pulley arrangement, as shown in the figure.

Correct answer

0

Step-by-step solution

A hanging mass M is connected to a four times bigger mass by using a string pulley arrangement, as shown in the figure.

Equation for 4M:2Mg−T=4Ma...(1)4M: 2Mg - T = 4Ma . . . \left(1\right)

Equation for M:T−Mg=Ma...(2)M: T - Mg = Ma . . . \left(2\right)

Adding both equation we get,

Mg=5Ma⇒a=g5Mg = 5Ma ⇒ a = \dfrac{g}{5}

Now, tension T=Mg+Ma=6Mg5T = Mg + Ma = \dfrac{6Mg}{5}

Therefore, x=6x = 6

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