A force on an object of mass 100 g is 10 i ^ + 5 j ^ N . The position of that object at t = 2 s is a i ^ + b j ^ m after starting from rest. The value of a b will be _____ .

Step-by-step solution

a → = F → m = 10 i ^ + 5 j ^ 0 . 1 = 100 i ^ + 50 j ^ Displacement covered in vector form can be written as, s → = u → t + 1 2 a → t 2 ⇒ s → = 1 2 100 i ^ + 50 j ^ 2 2 , ⇒ s → = 200 i ^ + 100 j ^ Comparing it with, s → = a i ^ + b j ^ , we get a = 200   &   b = 100 Therefore, a b = 2