A force → F = ( 40 ^ i + 10 ^ j ) N acts on a body of mass 5kg . If...

\dfrac{d\overset{\to}{v}}{dt} = \overset{\to}{a} = \overset{\to}{F}m = ( 8\overset{^}{i} + 2\overset{^}{j} ) m{s}^{- 2}

\dfrac{d\overset{\to}{r}}{dt} = \overset{\to}{v} = ( 8t\overset{^}{i} + 2t\overset{^}{j} ) m{s}^{- 1}

\overset{\to}{r} = ( \overset{^}{i} + 2\overset{^}{j} ) \dfrac{{t}^{2}}{2}m

At $t = 10sec$

\overset{\to}{r} = [ ( 8\overset{^}{i} + 2\overset{^}{j} ) 50 ] m

⇒ \overset{\to}{r} = ( 400\overset{^}{i} + 100\overset{^}{j} ) m