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JEE Main 202120 JulyEvening Shift
Exam
JEE Main
Year
2021
Date
20 July
Shift
Evening Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2021 · 20 July · Evening Shift · Physics · Laws of Motion

A body of mass m is launched up on a rough inclined plane making an...

A body of mass mm is launched up on a rough inclined plane making an angle of 30°30 ° with the horizontal. The coefficient of friction between the body and plane is x5\dfrac{\sqrt{x}}{5} if the time of ascent is half of the time of descent. The value of xx is

Correct answer

0

Step-by-step solution

{t}_{a} = \dfrac{1}{2}{t}_{d}</p><p></p><p>\sqrt{\dfrac{2s}{{a}_{a}}} = \dfrac{1}{2}\sqrt{\dfrac{2s}{{a}_{d}}} \ldots \left(i\right)</p><p></p><p>{a}_{a} = gsin\theta + \mu gcos\theta</p><p></p><p>= \dfrac{g}{2} + \dfrac{\sqrt{3}}{2}\mug</p><p></p><p>{a}_{d} = gsin\theta - \mu gcos\theta</p><p></p><p>= \dfrac{g}{2} - \dfrac{\sqrt{3}}{2}\mug</p><p>Usingtheabovevaluesof</p><p>Using the above values of{a}_{a}andand{a}_{d}andputtingin<br/>equation(i)and putting in<br />equation \left(i\right), we will get, μ=35\mu = \dfrac{\sqrt{3}}{5}

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