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JEE Main 202118 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
18 March
Shift
Morning Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2021 · 18 March · Morning Shift · Physics · Laws of Motion

A bullet of mass 0 . 1kg is fired on a wooden block to pierce...

A bullet of mass 0.1kg0 . 1kg is fired on a wooden block to pierce through it, but it stops after moving a distance of 50cm50cm into it. If the velocity of the bullet before hitting the wood is 10ms−110m{s}^{- 1} and, it slows down with uniform deceleration, then the magnitude of effective retarding force on the bullet is xN.xN . The value of xx to the nearest integer is,

Correct answer

0

Step-by-step solution

v2=u2+2as{v}^{2} = {u}^{2} + 2as⇒0=(10)2+2(−a)(12)⇒ 0 = ( 10{)}^{2} + 2 ( - a ) \left(\dfrac{1}{2}\right)
⇒a=100ms−2⇒ a = 100m{s}^{- 2}
⇒F=ma=(0.1)(100)=10N⇒ F = ma = ( 0 . 1 ) ( 100 ) = 10N
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