JEE Main202116 Mar 2021Morning ShiftPhysicsLaws of MotionActual
A block of mass m slides along a floor while a force of magnitude F is applied to it at an angle θ as shown in figure. The coefficient of kinetic friction is μ K . Then, the block's acceleration a is given by : ( g is acceleration due to gravity)
Options
- A- F m cos θ - μ K g - F m sin θ
- BF m cos θ - μ K g - F m sin θ
- CF m cos θ - μ K g + F m sin θ
- DF m cos θ + μ K g - F m sin θ
Correct answer
B. F m cos θ - μ K g - F m sin θ
Step-by-step solution
N = m g - f sin θ F cos θ - μ k N = m a F cos θ - μ k m g - F sin θ = m a a = F m cos θ - μ K g - F m sin θ