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JEE Main 20205 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
5 September
Shift
Evening Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2020 · 5 September · Evening Shift · Physics · Laws of Motion

A spaceship in space sweeps stationary interplanetary dust. As a...

A spaceship in space sweeps stationary interplanetary dust. As a result, its mass increases at a rate dM(t)dt=bv2(t),\dfrac{dM ( t )}{dt} = b{v}^{2} ( t ) , where v(t)v ( t ) is its instantaneous velocity. The instantaneous acceleration of the satellite is:

Options

  1. A−bv3(t)- b{v}^{3} ( t )
  2. B−bv3M(t)\dfrac{- b{v}^{3}}{M ( t )}
  3. C−2bv3M(t)- \dfrac{2b{v}^{3}}{M ( t )}
  4. D−bv32M(t)- \dfrac{b{v}^{3}}{2M ( t )}

Correct answer

B. −bv3M(t)\dfrac{- b{v}^{3}}{M ( t )}

Step-by-step solution

dM(t)dt=−bv2\dfrac{dM ( t )}{dt} = - {bv}^{2}
in free space no external force so there in only thrust force on rocket
fin=dMdt(Vrel){f}_{in} = \dfrac{dM}{dt}\left({V}_{rel}\right)
Ma=(−bv2(t))vMa = \left(\dfrac{- b{v}^{2}}{( t )}\right)v
a=−bv3M(t)a = \dfrac{- {bv}^{3}}{M ( t )}
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