A mass of 10 k g is suspended by a rope of length 4 m , from the ceiling. A force F is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of 45 ° with the vertical. Then F equals: (Take g = 10 m s - 2 and the rope to be massless)

Step-by-step solution

Let the tension in the string is T . Applying the condition of equilibrium in the vertical direction, T cos 45 ° = 100 ⇒   T 2 = 100 . . . 1 In the horizontal direction, T sin 45 ° = F ⇒   T 2 = F Put the value of T from equation 1 , ⇒   F = 100   N So, the horizontal force applied on the rope will be 100   N .