JEE Main 201910 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 10 April
- Shift
- Evening Shift
- Subject
- Physics
- Chapter
- Laws of Motion
JEE Main 2019 · 10 April · Evening Shift · Physics · Laws of Motion
Two blocks A and B of masses m _ A = 1kg and m _ B = 3kg are kept...
Two blocks and of masses and are kept on the table as shown in figure. The coefficients of friction between and is and between and the surface of the table is also The maximum force that can be applied on horizontally, so that the block does not slide over the block is : [Take ]

Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
Maximum possible acceleration of block

For block not to slide the maximum acceleration of both blocks should be

{F}_\max - µmg = m{a}_\max
{F}_\max - 0.2 \times 4 \times 10 = 4 \times 2
{F}_\max - 8 = 8
{F}_\max = 16N
For block not to slide the maximum acceleration of both blocks should be
{F}_\max - µmg = m{a}_\max
{F}_\max - 0.2 \times 4 \times 10 = 4 \times 2
{F}_\max - 8 = 8
{F}_\max = 16N