JEE Main2018PhysicsLaws of MotionActual
Two masses m 1 = 5 kg and m 2 = 10 kg , connected by an inextensible string over a frictionless pulley, are moving as shown in the figure. The coefficient of friction of horizontal surface is 0 . 15 . The minimum weight m that should be put on top of m 2 to stop the motion is:
Options
- A10 .3   kg
- B18 .3   kg
- C27 .3   kg
- D43 .3   kg
Correct answer
C. 27 .3   kg
Step-by-step solution
T = 5 g ⇒ μ 10 + m ≥ 5 g ⇒ 10 + m ≥ 5 0.15 ⇒ m ≥ 23.33   k g ⇒ m = 27.3   kg .