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JEE Main 20188 April
Exam
JEE Main
Year
2018
Date
8 April
Subject
Physics
Chapter
Laws of Motion

JEE Main 2018 · 8 April · Physics · Laws of Motion

Two masses m _ 1 = 5kg and m _ 2 = 10kg , connected by an...

Two masses m1=5kg{m}_{1} = 5kg and m2=10kg{m}_{2} = 10kg, connected by an inextensible string over a frictionless pulley, are moving as shown in the figure. The coefficient of friction of horizontal surface is 0.150 . 15. The minimum weight m that should be put on top of m2{m}_{2} to stop the motion is:

Two masses m _ 1 = 5kg and m _ 2 = 10kg , connected by an inextensible string over a frictionless pulley, are moving as

Options

  1. A10.3kg10 .3 kg
  2. B18.3kg18 .3 kg
  3. C27.3kg27 .3 kg
  4. D43.3kg43 .3 kg

Correct answer

C. 27.3kg27 .3 kg

Step-by-step solution

T=5g⇒μ(10+m)≥5g⇒10+m≥50.15T = 5g⇒ \mu\left(10 + m\right) \ge 5g⇒ 10 + m \ge \dfrac{5}{0.15}
⇒m≥23.33kg⇒m=27.3kg⇒ m \ge 23.33kg⇒ m = 27.3kg.
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