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JEE Main 201610 AprilOnline
Exam
JEE Main
Year
2016
Date
10 April
Mode
Online
Subject
Physics
Chapter
Laws of Motion

JEE Main 2016 · 10 April · Online · Physics · Laws of Motion

A particle of mass m is acted upon by a force F given by the...

A particle of mass mm is acted upon by a force FF given by the empirical law F=Rt2v(t).F = \dfrac{R}{{t}^{2}}v\left(t\right) . If this law is to be tested experimentally by observing the motion starting from rest, the best way is to plot

Options

  1. Alogv(t)against1tlog v\left(t\right)against\dfrac{1}{t}
  2. Bv(t)againstt2\left(t\right)against{t}^{2}
  3. Clogv(t)against1t2log v\left(t\right)against\dfrac{1}{{t}^{2}}
  4. Dlogv(t)againsttlog v\left(t\right)againstt

Correct answer

A. logv(t)against1tlog v\left(t\right)against\dfrac{1}{t}

Step-by-step solution

F=Rt2v(t)⇒mdvdt=Rt2v(t)F = \dfrac{R}{{t}^{2}}v\left(t\right) ⇒ m\dfrac{dv}{dt} = \dfrac{R}{{t}^{2}}v\left(t\right)

∫dvv=∫Rdtmt2∫ \dfrac{dv}{v} = ∫ \dfrac{Rdt}{m{t}^{2}}

ln v=−Rmtv = - \dfrac{R}{mt}

∴ln⁡v∝1t∴ \ln v ∝ \dfrac{1}{t}
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