A block of mass m is placed on a surface with a vertical cross section given by y = x 3 6 . If the coefficient of friction is 0 . 5 , the maximum height above the ground at which the block can be placed without slipping is

Step-by-step solution

For block remain stationary. μ = tan θ   ( θ is angle at that point) ∴ tan θ = μ = 1 2 (slope) y = x 3 6 ∴ d y d x = 3 x 2 6 = x 2 2 ⇒ slope = 1 2 ⇒ x = 1 ∴ y = (1) 3 6 = 1 6 m