Sand is being dropped on a conveyer belt at the rate of 2 ~kg per second. The force necessary to keep the belt moving with a constant speed of 3 ~ms^ -1 will be

Correct answer: B. 6 ~N Here, rate of fall of sand on conveyer belt, (d m)/(d t)= 2 ~kg ~s^ -1 Conveyer belt speed v=3 ~ms^ -1 Force F= ? F=v (d m)/(d t)= 3 × 2=6 ~N

JEE Main 201219 MayOnline

Exam: JEE Main
Year: 2012
Date: 19 May
Mode: Online
Subject: Physics
Chapter: Laws of Motion

JEE Main 2012 · 19 May · Online · Physics · Laws of Motion

Sand is being dropped on a conveyer belt at the rate of 2 ~kg per...

Sand is being dropped on a conveyer belt at the rate of

2 \mathrm{~kg}

per second. The force necessary to keep the belt moving with a constant speed of

3 \mathrm{~ms}^{-1}

will be

Options

A $12 \mathrm{~N}$
B $6 \mathrm{~N}$
Czero
D $18 \mathrm{~N}$

Correct answer

B. $6 \mathrm{~N}$

Step-by-step solution

Here, rate of fall of sand on conveyer belt,

\frac{d m}{d t}=

\mathrm{~kg} \mathrm{~s}^{-1}

Conveyer belt speed

v=3 \mathrm{~ms}^{-1}

Force

F=

? F=v

\frac{d m}{d t}=

\times

2=6

\mathrm{~N}

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