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JEE Main 201219 MayOnline
Exam
JEE Main
Year
2012
Date
19 May
Mode
Online
Subject
Physics
Chapter
Laws of Motion

JEE Main 2012 · 19 May · Online · Physics · Laws of Motion

Two point masses of mass m_1=f M and m_2=(1-f) M(f < 1) are in...

Two point masses of mass m1=fMm_1=f M and m2=(1−f)M(f<1)m_2=(1-f) M(f < 1) are in outer space (far from gravitational influence of other objects) at a distance RR from each other. They move in circular orbits about their centre of mass with angular velocities ω1\omega_1 for m1m_1 and ω2\omega_2 for m2m_2. In that case

Options

  1. A(1−f)ω1=fω(1-f) \omega_1=f \omega
  2. Bω1=ω2\omega_1=\omega_2 and independent of ff
  3. Cfω1=(1−f)ω2f \omega_1=(1-f) \omega_2
  4. Dω1=ω2\omega_1=\omega_2 and depend on ff

Correct answer

B. ω1=ω2\omega_1=\omega_2 and independent of ff

Step-by-step solution

Angular velocity is the angular displacement per unit time i.e., ω=ΔθΔt\omega=\frac{\Delta \theta}{\Delta t} Here w1=w2w_1=w_2 and independent of ff.
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