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JEE Main2003PhysicsLaws of MotionActual

A marble block of mass 2 ~kg lying on ice when given a velocity of 6 ~m / s is stopped by friction in 10 ~s . Then the coefficient of friction is

Options

  1. A0.02
  2. B0.03
  3. C0.04
  4. DNone of these

Correct answer

D. None of these

Step-by-step solution

a= g= 6 10 [ using v = u + at ] = 6 10 g = 6 10 10 =0.06

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