JEE Main20264 April 2026Evening ShiftPhysicsMagnetic Effects of CurrentActual
A circular coil of radius 2 cm and 125 turns carries a current of 1 A. The coil is placed in a uniform magnetic field of magnitude 0.4 T. The axis of the coil makes an angle of 30° with the direction of the magnetic field. The torque acting on the coil is 10⁻⁴ N.m. The value of is ______. ( =3.14 )
Correct answer
0
Step-by-step solution
The magnetic moment of the coil is given by M = NIA . The torque acting on the coil is = MB = NIAB . Substituting the given values: = 125 1 ( (0.02)^2) 0.4 30^ = 125 1 4 10⁻⁴ 0.4 0.5 = 100 10⁻⁴ = 100 3.14 10⁻⁴ = 314 10⁻⁴ N.m Comparing with 10⁻⁴ N.m, we get = 314 . Answer: 314