The vertical component of the earth's magnetic field is 6 × 10 ^ -...

Given here:

The vertical component of the earths magnetic field ${B}_{V} = 6 \times {10}^{- 5}T$ and angle of dip $\delta = 37 °$.

For vertical component, ${B}_{V} = Bsin\delta$

Putting the values, we have

$⇒ 6 \times {10}^{- 5} = B\dfrac{3}{5}$

Earth's magnetic field at that place as $B = 10 \times {10}^{- 5}T$ $= {10}^{- 4}T$